Jury
Trilemma:
1. No punishing juries for a decision not based on the law and evidence.
2. No double jeopardy.
3. No jury nullifiication.
A legal system can have any two of these but not all three.
***
Spinning numbers:
Voter A: u = -1, v = 0, w = 1
Voter B: u = 0, v = 1, w = -1
Voter C: u = 1, v = -1, w = 0
Therefore this trilemma:
u < v ;
v < w ;
w < u
though all agree that the order is linear, within {-1,0,1}.
***
1/3 of two things:
Let x equal sqrt(u) when this is defined on the reals;
then x is 0 or 1 or nil (meaning not existing).
Similarly let y = sqrt(v) ; and z = sqrt(w) :
Voter A: x = nil, y = 0, z = 1
Voter B: x = 0, y = 1, z = nil
Voter C: x = 1, y = nil, z = 0
Unanimous:
{x,y,z} has two elements; 0, 1 and nil.
the three are distinct because one doesn't exist
Majorities:
x exists
y exists
z exists
x and y do not co-exist
y and z do not co-exist
z and x do not co-exist
x is not 0
x is not 1
x is 0 or 1
y is not 0
y is not 1
y is 0 or 1
z is not 0
z is not 1
z is 0 or 1
***
2/3 of one thing:
Let x = sqrt(u(1-u)), y = sqrt(v(1-v)), z = sqrt(w(1-w)), when these are defined in the reals.
Voter A: x = nil, y = 0, z = 0
Voter B: x = 0, y = 0, z = nil
Voter C: x = 0, y = nil, z = 0
Unanimous:
{x,y,z} has one element; 0 twice, and nil.
Majorities:
x exists
y exists
z exists
x and y do not co-exist
y and z do not co-exist
z and x do not co-exist
x = 0
y = 0
z = 0
x not = y
y not = z
z not = x
***
1/3 of one thing:
Let x = sqrt(u-1), y = sqrt(v-1), z = sqrt(w-1), when these are defined in the reals.
Voter A: x = nil, y = nil, z = 0
Voter B: x = nil, y = 0, z = nil
Voter C: x = 0, y = nil, z = nil
Unanimous:
{x,y,z} has one element; 0, and nil twice.
Majorities:
x does not exist and x is not 0
y does not exist and y is not 0
z does not exist and z is not 0
x or y exists and equals 0
y or z exists and equals 0
z or x exists and equals 0
x and y do not equally exist
y and z do not equally exist
z and x do not equally exist
1. No punishing juries for a decision not based on the law and evidence.
2. No double jeopardy.
3. No jury nullifiication.
A legal system can have any two of these but not all three.
***
Spinning numbers:
Voter A: u = -1, v = 0, w = 1
Voter B: u = 0, v = 1, w = -1
Voter C: u = 1, v = -1, w = 0
Therefore this trilemma:
u < v ;
v < w ;
w < u
though all agree that the order is linear, within {-1,0,1}.
***
1/3 of two things:
Let x equal sqrt(u) when this is defined on the reals;
then x is 0 or 1 or nil (meaning not existing).
Similarly let y = sqrt(v) ; and z = sqrt(w) :
Voter A: x = nil, y = 0, z = 1
Voter B: x = 0, y = 1, z = nil
Voter C: x = 1, y = nil, z = 0
Unanimous:
{x,y,z} has two elements; 0, 1 and nil.
the three are distinct because one doesn't exist
Majorities:
x exists
y exists
z exists
x and y do not co-exist
y and z do not co-exist
z and x do not co-exist
x is not 0
x is not 1
x is 0 or 1
y is not 0
y is not 1
y is 0 or 1
z is not 0
z is not 1
z is 0 or 1
***
2/3 of one thing:
Let x = sqrt(u(1-u)), y = sqrt(v(1-v)), z = sqrt(w(1-w)), when these are defined in the reals.
Voter A: x = nil, y = 0, z = 0
Voter B: x = 0, y = 0, z = nil
Voter C: x = 0, y = nil, z = 0
Unanimous:
{x,y,z} has one element; 0 twice, and nil.
Majorities:
x exists
y exists
z exists
x and y do not co-exist
y and z do not co-exist
z and x do not co-exist
x = 0
y = 0
z = 0
x not = y
y not = z
z not = x
***
1/3 of one thing:
Let x = sqrt(u-1), y = sqrt(v-1), z = sqrt(w-1), when these are defined in the reals.
Voter A: x = nil, y = nil, z = 0
Voter B: x = nil, y = 0, z = nil
Voter C: x = 0, y = nil, z = nil
Unanimous:
{x,y,z} has one element; 0, and nil twice.
Majorities:
x does not exist and x is not 0
y does not exist and y is not 0
z does not exist and z is not 0
x or y exists and equals 0
y or z exists and equals 0
z or x exists and equals 0
x and y do not equally exist
y and z do not equally exist
z and x do not equally exist
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