Paradox of the Frog
This
paradox unites the paradox of the boundary with the paradox of infinite parity.
It’s
a sunny day at the frog pond, but a large tree is casting a dark shadow. A frog
is sitting a foot into the shade. Feeling too cold, the frog jumps out of the
shade and lands 1/2 foot into the bright sunlight. Feeling too warm, the frog
jumps out of the sunlight and lands 1/4 foot into the shade. Feeling too cold,
the frog jumps out of the shade and lands 1/8 foot into the bright sunlight.
Feeling too warm, the frog jumps out of the sunlight and lands 1/16 foot into
the shade. And so on; moreover, the frog’s jumps accelerate geometrically, so
they are all done in finite time.
When
the frog finally settles on the shade line, it has alternated between warm and
cold infinitely many times. On the shade line, is the frog warm or cold?
If,
like Baby Bear’s porridge, the frog is ‘just right’, then that’s a third value
in addition to ‘warm’ or ‘cold’. The third value arises from an infinite
alternation of the other two; so this is like asking if infinity is odd or
even.
Now
let us take into account the movement of the shadow. Upon reaching the shade
line, the frog enters Samadhi; but then awakes an hour later to find the shade
line shifted. It then makes another infinity of jumps, reaches the shade line
again, and goes back to sleep. Then the shadow-line moves, and the process
repeats.
By
appropriately adjusting the frog’s times of waking and sleeping, we can make
the frog go through any countable infinite ordinal sequence of jumps in the
course of the day. Let the number of frog jumps by the end of the day to be a
large countable infinite ordinal; large enough, say, to exceed any recursive
ordinal naming scheme. All though that busy day the frog was warm, cold or
asleep. At the moment of sunset, is the frog awake or asleep? And if awake,
warm or cold?
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