On Prime-to-Prime Numbers
Once, at the gym, I realized that I’d rather do 12 rounds of push-ups than 10; and this is because I would count off the rounds, and I liked it when the fraction of the total reduced. (The reductions took my mind off the push-ups. I like having done push-ups, but I hate doing them.)
2 rounds of 12 is one-sixth; 3 is one-fourth; 4 is one-third; 6 is one-half; 8 is two thirds; 9 is three quarters; and 10 is five sixths. But with 10 rounds, the only fractions that reduce are 2/10, 4/10, 5/10, 6/10, and 8/10. 3, 7, and 9 are relatively prime to 10, but 9 is not prime; whereas 5, 7, and 11 are relatively prime to 12, and all of them are prime.
So of all the numbers between 1 and 12, twelve is relatively prime only to primes. This is a property not shared by ten; therefore my preference for 12 over 10 push-ups.
So define a prime-to-prime number (or workout number) as a number W such that, if N is an integer between 1 and W, and N is relatively prime to W, then N is prime.
Here are some theorems:
Any prime-to-prime number is less than the square of the smallest prime not in its prime factorization.
Proof:
If W is prime-to-prime, and p is the smallest prime not in its factorization, then W is relatively prime to p2, which is not a prime. So by definition of prime-to-prime, W is not greater than p2; and by definition of p, W does not equal p2; therefore W is less than p2.
QED.
The largest prime-to-prime number is 30.
Proof:
If W is prime-to-prime, and W>30, then W>4=22 ; and W>9=32 ; and W>25=52. Therefore W has factors 2, 3, and 5:
W = 2*3*5*k = 30k, for some k.
So if W>30, then W is at least 60, so W>49=72. Therefore W has factors 2, 3, 5, and 7:
W = 2*3*5*7k = 210k, for some k.
So W is at least 210; so W>121=112. Therefore W has factors 2, 3, 5, 7, and 11:
W = 2*3*5*7*11k = 2310k, for some k.
And so on! W has factors 2, 3, 5, 7, 11, endlessly!*
Therefore W is infinite, that is, nonexistent.
Therefore no prime-to-prime numbers are greater than 30.
QED.
*note: The product 2*3*5*…*pn (for pn the nth prime) is greater than (pn)2, for n>2. This is because:
2*3*5*…*pn = 3*5*…* pn-2*2pn-1*pn
> 3*5*…* pn-2*pn*pn
= 3*5*…* pn-2*(pn)2
> (pn)2
The first inequality is due to Bertrand’s Theorem:
2pn-1 > pn
There are ten prime-to-prime numbers:
1, 2, 3, 4, 6, 8, 12, 18, 24, 30
Proof is by inspection of all integers from 1 to 30.
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